问题标题:
一道数学三角函数化简题(asin派/5+bcos派/5)/(acos派/5-bsin派/5)=(tan派/5+b/a)/(1-b/a﹡tan派/5)为什么啊.
更新时间:2024-05-07 01:31:59
问题描述:

一道数学三角函数化简题

(asin派/5+bcos派/5)/(acos派/5-bsin派/5)=(tan派/5+b/a)/(1-b/a﹡tan派/5)为什么啊.

罗茂松回答:
  右=(tanπ/5+b/a)/(1-b/a*tanπ/5)右=(sinπ/5/cosπ/5+b/a)/(1-b/a*sinπ/5/cosπ/5)分子、分母同乘a*cosπ/5右=(asinπ/5+bcosπ/5)/(a*cosπ/5-bsinπ/5)左=(asinπ/5+bcosπ/5)/(a*cosπ/5-bsinπ/5)所以:左=...
查看更多
数学推荐
热门数学推荐