问题标题:
√1+2sin(π/2+α)cos(π/2-α)=___.
更新时间:2024-04-28 01:06:52
问题描述:
√1+2sin(π/2+α)cos(π/2-α)=___.
蔡丽梅回答:
原式=√[(1+2sin(π/2+α)cos(π/2-α))]
=√(1+2cosαsinα)
=√[(sin²α+cos²α)+2cosαsinα]
=√(sinα+cosα)²
=∣sinα+cosα∣
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√1+2sin(π/2+α)cos(π/2-α)=___.