问题标题:
请问x3-6x2+ax+b=(x-1)(x-3)(?)a=?b=?
更新时间:2024-04-29 14:37:18
问题描述:
请问x3-6x2+ax+b=(x-1)(x-3)(?)a=?b=?
廖晓峰回答:
x3-6x2+ax+b=(x-1)(x-3)(cx+d)=(x^2-4x+3)(cx+d)=cx^3+dx^2-4cx^2-4dx+3cx+3d
c=1d-4c=-6-4d+3c=a3d=b
c=1d=-2b=-6a=11
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请问x3-6x2+ax+b=(x-1)(x-3)(?)a=?b=?